char a;
cin>>a;
if(a>='a'&&a<='z'){
a=a-32;
cout<<a;
}else if(a>='A'&&a<='Z'){
a=a+32;
cout<<a;
}else if(a>='0'&&a<='9'){
a=57-a;
cout<<a;
}else{
cout<<a;
}
| Problem 1096 >> 太难了 |
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dingyiyi @ 2023-08-17 09:30:54
char a;
cin>>a; if(a>='a'&&a<='z'){ a=a-32; cout<<a; }else if(a>='A'&&a<='Z'){ a=a+32; cout<<a; }else if(a>='0'&&a<='9'){ a=57-a; cout<<a; }else{ cout<<a; } |
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dingyiyi @ 2023-08-17 09:39:44
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tangzhicheng @ 2023-08-17 10:52:55
哪题
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pengyubo @ 2023-08-18 10:50:29
#include<iostream>
using namespace std; int main(){ string n; int C=0; cin>>n; for(int i=0;i<n.size();i++){ if(n[i]>='a'&&n[i]<='z'){ n[i]-=32; } } int j[26]={0}; for(int i=0;i<n.size();i++){ j[n[i]-'A']++; C++; if(n[i+1]!=n[i]){ C=0; if(j[n[i]-'A']!=0){ char m=i+'A'; cout<<"("<<m<<","<<j[i]<<")"; } } } return 0; } |
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dingyiyi @ 2023-08-24 10:03:48
lj
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zhanglinfeng @ 2023-10-05 11:37:49
这么简单
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zhangxuanzhen @ 2023-10-05 11:56:06
哪哪题题
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xuzerui @ 2023-10-05 11:57:54
#include<bits/stdc++.h>
using namespace std; long long a[100005]; long long b[100005]; long long c[200005]; int main(){ long long n; scanf("%lld",&n); for(int i=1;i<=n;i++){ scanf("%lld",&a[i]); if(a[i]==0){ a[i]=-1; } } c[0]=0; long long maxx=0; for(long long i=1;i<=n;i++){ b[i]=a[i]+b[i-1]; if(b[i]!=0){ if(c[b[i]+100000]==0){ c[b[i]+100000] =i; }else{ long long l; l=i-c[b[i]+100000]; maxx=max(maxx,l); } }else{ maxx=max(maxx,i); } } cout<<maxx; return 0; } |
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xuzerui @ 2023-10-05 15:28:10
#include<bits/stdc++.h>
using namespace std; int main(){ int n,x; cin>>n>>x; string s; if(n==0){ cout<<0; }else{ while(n!=0){ if(n%x>9){ char b=n%x-10+'A'; s=b+s; }else{ char a=n%x+'0'; s=a+s; } n/=x; } cout<<s; } return 0; } |
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zhaodongqiang @ 2023-12-27 20:38:33
r
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zhaodongqiang @ 2023-12-27 20:38:43
有人吗
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zhaodongqiang @ 2023-12-27 20:39:13
讨论吧怎么没了
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zhaodongqiang @ 2024-06-29 15:10:20
#include<bits/stdc++.h>
using namespace std; int main() { char a; cin>>a; if(a>='a'&&a<='z'){ a=a-32; cout<<a; }else if(a>='A'&&a<='Z'){ a=a+32; cout<<a; }else if(a>='0'&&a<='9'){ //'9'-'0' = 57-48 = 9 a='9'-a+'0'; cout<<a; }else{ cout<<a; } return 0; } |